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5r^2-9r-44=0
a = 5; b = -9; c = -44;
Δ = b2-4ac
Δ = -92-4·5·(-44)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-31}{2*5}=\frac{-22}{10} =-2+1/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+31}{2*5}=\frac{40}{10} =4 $
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